Mercurial > hg > mercurial-crew-with-dirclash
comparison mercurial/localrepo.py @ 4648:8e503fa54d2d
Add option to heads to show only heads for current branch.
| author | Eric Hopper <hopper@omnifarious.org> |
|---|---|
| date | Tue, 19 Jun 2007 08:37:43 -0700 |
| parents | 63b9d2deed48 |
| children | fc389dcc33f5 0403b80352c9 |
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| 4647:7c80e3e6f030 | 4648:8e503fa54d2d |
|---|---|
| 1016 heads = self.changelog.heads(start) | 1016 heads = self.changelog.heads(start) |
| 1017 # sort the output in rev descending order | 1017 # sort the output in rev descending order |
| 1018 heads = [(-self.changelog.rev(h), h) for h in heads] | 1018 heads = [(-self.changelog.rev(h), h) for h in heads] |
| 1019 heads.sort() | 1019 heads.sort() |
| 1020 return [n for (r, n) in heads] | 1020 return [n for (r, n) in heads] |
| 1021 | |
| 1022 def branchheads(self, branch, start=None): | |
| 1023 branches = self.branchtags() | |
| 1024 if branch not in branches: | |
| 1025 return [] | |
| 1026 # The basic algorithm is this: | |
| 1027 # | |
| 1028 # Start from the branch tip since there are no later revisions that can | |
| 1029 # possibly be in this branch, and the tip is a guaranteed head. | |
| 1030 # | |
| 1031 # Remember the tip's parents as the first ancestors, since these by | |
| 1032 # definition are not heads. | |
| 1033 # | |
| 1034 # Step backwards from the brach tip through all the revisions. We are | |
| 1035 # guaranteed by the rules of Mercurial that we will now be visiting the | |
| 1036 # nodes in reverse topological order (children before parents). | |
| 1037 # | |
| 1038 # If a revision is one of the ancestors of a head then we can toss it | |
| 1039 # out of the ancestors set (we've already found it and won't be | |
| 1040 # visiting it again) and put its parents in the ancestors set. | |
| 1041 # | |
| 1042 # Otherwise, if a revision is in the branch it's another head, since it | |
| 1043 # wasn't in the ancestor list of an existing head. So add it to the | |
| 1044 # head list, and add its parents to the ancestor list. | |
| 1045 # | |
| 1046 # If it is not in the branch ignore it. | |
| 1047 # | |
| 1048 # Once we have a list of heads, use nodesbetween to filter out all the | |
| 1049 # heads that cannot be reached from startrev. There may be a more | |
| 1050 # efficient way to do this as part of the previous algorithm. | |
| 1051 | |
| 1052 set = util.set | |
| 1053 heads = [self.changelog.rev(branches[branch])] | |
| 1054 # Don't care if ancestors contains nullrev or not. | |
| 1055 ancestors = set(self.changelog.parentrevs(heads[0])) | |
| 1056 for rev in xrange(heads[0] - 1, nullrev, -1): | |
| 1057 if rev in ancestors: | |
| 1058 ancestors.update(self.changelog.parentrevs(rev)) | |
| 1059 ancestors.remove(rev) | |
| 1060 elif self.changectx(rev).branch() == branch: | |
| 1061 heads.append(rev) | |
| 1062 ancestors.update(self.changelog.parentrevs(rev)) | |
| 1063 heads = [self.changelog.node(rev) for rev in heads] | |
| 1064 if start is not None: | |
| 1065 heads = self.changelog.nodesbetween([start], heads)[2] | |
| 1066 return heads | |
| 1021 | 1067 |
| 1022 def branches(self, nodes): | 1068 def branches(self, nodes): |
| 1023 if not nodes: | 1069 if not nodes: |
| 1024 nodes = [self.changelog.tip()] | 1070 nodes = [self.changelog.tip()] |
| 1025 b = [] | 1071 b = [] |