view mercurial/ancestor.py @ 5440:f9b0e4f023c4

findcopies: fix rename bug We've fiddled with this line several times, and an old bug has reappeared from it. Let's take a peek at the history. The original "or" (rev 3674, in 0.9.2 and 0.9.3): http://www.selenic.com/hg/rev/9103dab96093 Then I changed it to an "and" to fix a bug (rev 4304): http://www.selenic.com/hg/rev/4787e2b0dd03 Then for reasons now lost in the mists of time, I dropped half (rev 4399): http://www.selenic.com/hg/rev/93652499bed3 Then we added back the "or" (rev 4416, in 0.9.4): http://www.selenic.com/hg/rev/bb1800a7d7e1 So it seems it ought to be "and".
author Matt Mackall <mpm@selenic.com>
date Mon, 08 Oct 2007 18:47:22 -0500
parents eb0b4a2d70a9
children
line wrap: on
line source

# ancestor.py - generic DAG ancestor algorithm for mercurial
#
# Copyright 2006 Matt Mackall <mpm@selenic.com>
#
# This software may be used and distributed according to the terms
# of the GNU General Public License, incorporated herein by reference.

import heapq

def ancestor(a, b, pfunc):
    """
    return the least common ancestor of nodes a and b or None if there
    is no such ancestor.

    pfunc must return a list of parent vertices
    """

    if a == b:
        return a

    # find depth from root of all ancestors
    visit = [a, b]
    depth = {}
    while visit:
        vertex = visit[-1]
        pl = pfunc(vertex)
        if not pl:
            depth[vertex] = 0
            visit.pop()
        else:
            for p in pl:
                if p == a or p == b: # did we find a or b as a parent?
                    return p # we're done
                if p not in depth:
                    visit.append(p)
            if visit[-1] == vertex:
                depth[vertex] = min([depth[p] for p in pl]) - 1
                visit.pop()

    # traverse ancestors in order of decreasing distance from root
    def ancestors(vertex):
        h = [(depth[vertex], vertex)]
        seen = {}
        while h:
            d, n = heapq.heappop(h)
            if n not in seen:
                seen[n] = 1
                yield (d, n)
                for p in pfunc(n):
                    heapq.heappush(h, (depth[p], p))

    def generations(vertex):
        sg, s = None, {}
        for g, v in ancestors(vertex):
            if g != sg:
                if sg:
                    yield sg, s
                sg, s = g, {v:1}
            else:
                s[v] = 1
        yield sg, s

    x = generations(a)
    y = generations(b)
    gx = x.next()
    gy = y.next()

    # increment each ancestor list until it is closer to root than
    # the other, or they match
    try:
        while 1:
            if gx[0] == gy[0]:
                for v in gx[1]:
                    if v in gy[1]:
                        return v
                gy = y.next()
                gx = x.next()
            elif gx[0] > gy[0]:
                gy = y.next()
            else:
                gx = x.next()
    except StopIteration:
        return None